Discussion
A noise figure of \( 3 \ \mathrm{dB} \) corresponds to an equivalent noise temperature of about
Answer: C
Converting through \( T_e = (F-1)T_0 \) with \( F = 2 \):
\[ T_e = (2-1) \times 290 = 290 \ \mathrm{K} \]
so 290 kelvin, which is the reference temperature itself and a useful anchor: 3 dB noise figure equals 290 K. 580 K would be 4.8 dB, and 145 K about 1.8 dB. Satellite and radio astronomy work uses noise temperature because the numbers are more informative at low noise figures, where decibels compress the differences.
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development