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Two frames \(S\) (solid lines) and \(S'\) (dashed lines) with common origin are shown in the figure below. Frame \(S\) is inertial while \(S'\) is rotating about the common \(z\)-axis. There is a point mass fixed at \(P\) on the \(x\)-axis of the \(S\) frame. The magnitude of the centrifugal force and the Coriolis force experienced by the mass in the \(S'\) frame is \(F_{cen}\) and \(F_{cor}\), respectively. Which of the following options is correct for these forces?

Solid x and y axes of frame S with point P on the x axis, and dashed x-prime and y-prime axes of frame S-prime rotated anticlockwise about the common origin

  • A.\(F_{cen} = 0\) and \(F_{cor} = 0\)
  • B.\(F_{cen} \neq 0\) and \(F_{cor} \neq 0\) and \(F_{cen} = \frac{F_{cor}}{2}\)
  • C.\(F_{cen} \neq 0\) and \(F_{cor} \neq 0\) and \(F_{cen} = 2F_{cor}\)
  • D.\(F_{cen} \neq 0\) and \(F_{cor} \neq 0\) and \(F_{cen} = F_{cor}\)

Answer: B

Both forces are non-zero, with \(F_{cen} = F_{cor}/2\).

In the rotating frame S' the mass, fixed in S at distance r from the axis, appears to move in a circle at speed \(v' = \omega r\), opposite to the frame's rotation. The fictitious forces are:

\[ \begin{aligned} F_{cen} &= m\omega^{2}r\ \text{(outward)} \\ F_{cor} &= 2m\omega v' = 2m\omega^{2}r\ \text{(inward)} \end{aligned} \]

Their sum is \(m\omega^{2}r\) inward, exactly the centripetal force needed for the circular motion seen in S', with no real force acting. The forces are not zero, because S' is rotating, and the Coriolis force is twice, not half or equal to, the centrifugal force, which rules out the remaining options.

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