Discussion
For a normal shock at \( M_1 = 2 \), the static pressure ratio \( p_2/p_1 \) is
Answer: C
The relation is \( p_2/p_1 = 1 + \frac{2\gamma}{\gamma+1}(M_1^2 - 1) \). With \( \gamma = 1.4 \) the coefficient is \( 2.8/2.4 = 1.1667 \), and \( M_1^2 - 1 = 3 \), so the ratio is \( 1 + 3.5 = 4.5 \). The pressure has more than quadrupled across a discontinuity a fraction of a micron thick.
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