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An engineer applies the isentropic relations straight through a normal shock. The results will be

  • A.Correct only at low upstream Mach numbers
  • B.Wrong, because entropy rises across the shock
  • C.Correct, since the shock is adiabatic
  • D.Correct for pressure but not for temperature

Answer: B

The isentropic relations assume constant entropy, which a shock plainly violates, so applying them through it is simply invalid. They remain perfectly good on either side of the shock; the Rankine-Hugoniot relations are what carry the flow across it.

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