Discussion
A normal shock at \( M_1 = 3 \) leaves the flow at a downstream Mach number nearest to
Answer: B
Substituting into \( M_2^2 = (1 + 0.2 M_1^2)/(1.4 M_1^2 - 0.2) \), the numerator is \( 1 + 1.8 = 2.8 \) and the denominator \( 12.6 - 0.2 = 12.4 \), so \( M_2^2 = 0.2258 \) and \( M_2 = 0.475 \). It is approaching, but has not reached, the limiting value of 0.378.
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