Discussion
The critical pressure ratio is \( ((\gamma+1)/2)^{\gamma/(\gamma-1)} \). For \( \gamma = 1.33 \) it is approximately
Answer: D
Correct answer: 1.85
Substituting \( \gamma = 1.33 \), which is representative of hot combustion products,
\[ \left(\frac{\gamma+1}{2}\right)^{\frac{\gamma}{\gamma-1}} = (1.165)^{4.03} \approx 1.85 \]so the nozzle chokes once the total-to-ambient pressure ratio reaches about 1.85. For cold air, with \( \gamma = 1.4 \), the figure is 1.89. The reciprocal, 0.53, is the critical pressure ratio written the other way up, as static over total.
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