Discussion
A nozzle has a coefficient of velocity of 0.98. Its ideal exit velocity of \( 600 \ \mathrm{m/s} \) becomes
Answer: C
Correct answer: 588 m/s
The coefficient of velocity is the ratio of actual to ideal exit velocity:
\[ V_e = C_v V_{ideal} = 0.98 \times 600 = 588 \text{ m/s} \]The two per cent shortfall represents friction and non-uniformity in the nozzle. A coefficient of velocity above unity is impossible, since the ideal is the isentropic case, so the answers above 600 m/s can be rejected without calculation.
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