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An engine's gross thrust is \( 45 \ \mathrm{kN} \) and its ram drag is \( 18 \ \mathrm{kN} \). Its net thrust is

  • A.63 kN
  • B.18 kN
  • C.45 kN
  • D.27 kN

Answer: D

Correct answer: 27 kN

Net thrust is what the airframe actually receives:

\[ F_n = F_g - F_{ram} = 45 - 18 = 27 \text{ kN} \]

Ram drag is the momentum of the incoming air, \( \dot{m}V_0 \), which the engine must first arrest; it is zero at rest and grows with flight speed. This is why an engine’s static rating always exceeds what it delivers in cruise.

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