Discussion
The radionuclide 135Te undergoes four successive β− emission to give the stable isotope :
Answer: D
The stable product is 135Ba.
Each β− emission turns a neutron into a proton: the mass number stays at 135 and the atomic number rises by one. Tellurium is element 52, so four successive emissions give:
\[ \begin{aligned} & {}^{135}_{52}\mathrm{Te} \rightarrow {}^{135}_{53}\mathrm{I} \rightarrow {}^{135}_{54}\mathrm{Xe} \\ & \rightarrow {}^{135}_{55}\mathrm{Cs} \rightarrow {}^{135}_{56}\mathrm{Ba} \end{aligned} \]
135I, 135Xe and 135Cs are the intermediates after one, two and three emissions; each is radioactive. 135Ba, element 56, is the stable end of this fission-product chain.
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