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When Uranium -235 (235U) is bombarded with neutron, fission occurs and the fragments formed are :

  • A.\(\mathrm{^{94}Kr + {}^{140}Ba + 2n}\)
  • B.\(\mathrm{^{94}Kr + {}^{139}Ba + 2n}\)
  • C.\(\mathrm{^{94}Kr + {}^{139}Xe + 2n}\)
  • D.\(\mathrm{^{94}Kr + {}^{140}Ba + 1n}\)

Answer: A

The fragments are 94Kr + 140Ba + 2n.

A nuclear equation must balance both mass number and atomic number. Neutron capture gives 236U (Z = 92):

\[ \begin{aligned} \text{mass: } & 235 + 1 = 94 + 140 + 2 = 236 \\ \text{charge: } & 92 = 36\ (\mathrm{Kr}) + 56\ (\mathrm{Ba}) \end{aligned} \]

With 139Ba and two neutrons, or 140Ba and one neutron, the mass numbers add to 235, one short. Xenon (Z = 54) with krypton gives a total charge of 90, not 92.

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