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Decay of one α-particle from Thorium (90Th232) will result in :

  • A.\({}_{90}\mathrm{Th}^{231}\)
  • B.\({}_{88}\mathrm{Ra}^{228}\)
  • C.\({}_{88}\mathrm{Ra}^{223}\)
  • D.\({}_{88}\mathrm{Ra}^{226}\)

Answer: B

The product is radium-228, 88Ra228.

An alpha particle is a helium nucleus with two protons and two neutrons. Emitting one lowers the atomic number by 2 and the mass number by 4:

\[ \begin{aligned} &{}_{90}\mathrm{Th}^{232} \\ &\rightarrow {}_{88}\mathrm{Ra}^{228} + {}_{2}\mathrm{He}^{4} \end{aligned} \]

Atomic number 88 is radium. This is the first step of the thorium decay series. 90Th231 keeps the atomic number and loses only one mass unit, which is not alpha decay. Radium-223 and radium-226 have the right element but the wrong mass number; radium-226 belongs to the uranium-238 series.

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