Discussion
The binding energy per nucleon for 107Ag47 nuclei is nearly :
[Given :
Mass of proton = 1.007825 amu
Mass of neutron = 1.008665 amu
Mass of silver = 106.905091 amu
1 amu = 931.5 MeV]
Answer: B
The binding energy per nucleon is nearly 8.54 MeV/nucleon.
Silver-107 has Z = 47 protons and N = 107 - 47 = 60 neutrons. The mass defect, using the hydrogen-atom mass for the proton so that the electrons cancel:
\[ \begin{aligned} \Delta m &= 47(1.007825) + 60(1.008665) \\ &\quad - 106.905091 \\ &= 107.887675 - 106.905091 \\ &= 0.982584\ \text{amu} \\ B &= 0.982584 \times 931.5 = 915.3\ \text{MeV} \\ B/A &= 915.3/107 = 8.55\ \text{MeV} \end{aligned} \]
That is close to the 8.5 MeV typical of medium nuclei. 8.10, 8.95 and 9.25 MeV/nucleon do not follow from these masses.
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