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The peak of a Kohler curve corresponds to

  • A.the radius at which the droplet first begins to freeze solid
  • B.the point at which the droplet falls as precipitation
  • C.the humidity at which the particle first deliquesces
  • D.the critical supersaturation for activating that particle

Answer: D

A droplet driven past the peak grows without limit at the ambient supersaturation and is said to be activated. Below the peak it settles at a stable equilibrium size and remains a haze droplet. The peak is therefore the dividing line between haze and cloud.

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