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'A' is older than 'B' but younger than 'C'. 'D' is younger than 'E' but older than 'A'. If 'C' is younger than 'D', who is the oldest of all ?

  • A.A
  • B.D
  • C.B
  • D.E

Answer: D

The oldest of all is E.

Write each statement as an inequality, with > meaning 'older than':

  • A is older than B but younger than C: C > A > B.
  • D is younger than E but older than A: E > D > A.
  • C is younger than D: D > C.

Combining them gives the full order E > D > C > A > B, so E is the oldest and B the youngest.

D is only the second oldest, because the second statement places E above D. A sits in the middle and B at the bottom, so neither can be the oldest.

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