Discussion
In a class of boys stands in a single line. One boy is nineteenth in order from both ends. How many boys are there in the class ?
Answer: B
There are 37 boys in the class.
The boy is 19th from each end, so there are 18 boys on each side of him:
\[ 18 + 1 + 18 = 37 \]
Equivalently, total = position from left + position from right \(-\) 1 \(= 19 + 19 - 1 = 37\). 38 would count the boy twice and is not offered; 27, 39 and 47 do not fit the symmetric position at all, since the total must be odd with him in the exact middle.
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