Discussion
Three persons A, B and C are standing in a queue. There are five persons between A and B and eight persons between B and C. If there be three persons ahead of C and 21 persons behind A, what could be the minimum number of persons in the queue?
Answer: C
Correct answer: 28
Three people stand ahead of C, so C is 4th. Eight people separate B from C, putting B at the 13th place, and five separate A from B, with A ahead of B at the 7th place. Twenty-one people stand behind A, so the queue holds \[ 7 + 21 = \mathbf{28} \]
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