Discussion
How many combinations of two-digit numners having 8 can be made from the following numbers?
8, 5, 2, 1, 7, 6
Answer: D
Correct answer: 11
With 8 as the first digit there are five numbers - 85, 82, 81, 87, 86 - and with 8 as the second digit another five: 58, 28, 18, 78, 68. Adding 88 itself gives \[ 5 + 5 + 1 = \mathbf{11} \]
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