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If 4 → 20, 5 → 30, 6 → 42, then 7 → ?

  • A.49
  • B.56
  • C.63
  • D.70

Answer: B

7 maps to 56.

Each number is multiplied by the next whole number:

\[ \begin{aligned} 4 \times 5 &= 20,\ 5 \times 6 = 30 \\ 6 \times 7 &= 42,\ 7 \times 8 = 56 \end{aligned} \]

Equivalently, \(n \rightarrow n^2 + n\). 49 is \(7^2\) alone, without the added 7; 63 is \(7 \times 9\) and 70 is \(7 \times 10\), which use the wrong second factor.

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