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Given two identical sequences: [4000, 400.0, 120.0, 60.0, 42.0, 37.8] and [1000, A, B, C, D, E]. What is the entry at the place of C for the second sequence?

  • A.9.45
  • B.10.5
  • C.15.0
  • D.30.0

Answer: C

The entry at C is 15.0.

Find the rule of the first sequence from the ratio of each term to the one before:

\[ \begin{aligned} 400/4000 &= 0.1,\ 120/400 = 0.3 \\ 60/120 &= 0.5,\ 42/60 = 0.7 \\ 37.8/42 &= 0.9 \end{aligned} \]

The multipliers are 0.1, 0.3, 0.5, 0.7, 0.9. Applying the same rule from 1000: A = 100, B = 30, C = 15, D = 10.5, E = 9.45. So 10.5 and 9.45 are the entries at D and E, and 30.0 is the entry at B; they are the off-by-one traps.

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