Discussion
Given two identical sequences: [4000, 400.0, 120.0, 60.0, 42.0, 37.8] and [1000, A, B, C, D, E]. What is the entry at the place of C for the second sequence?
Answer: C
The entry at C is 15.0.
Find the rule of the first sequence from the ratio of each term to the one before:
\[ \begin{aligned} 400/4000 &= 0.1,\ 120/400 = 0.3 \\ 60/120 &= 0.5,\ 42/60 = 0.7 \\ 37.8/42 &= 0.9 \end{aligned} \]
The multipliers are 0.1, 0.3, 0.5, 0.7, 0.9. Applying the same rule from 1000: A = 100, B = 30, C = 15, D = 10.5, E = 9.45. So 10.5 and 9.45 are the entries at D and E, and 30.0 is the entry at B; they are the off-by-one traps.
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development