Discussion
If each of the three nonzero numbers a, b and c is divisible by 3, then abc must be divisible by which by ?
Answer: B
Since each one of the three numbers aa, bb, and cc is divisible by 3, the numbers can be represented as 3p,3qand 3r respectively, where p,q and r are integers.
The product of the three numbers is 3p×3q×3r=27(pqr).
Since p,qp,q and rr are integers, pqrpqr is an integer and therefore abcabc is divisible by 27.
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