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What is the remainder left after dividing 1!+2!+3!.....+100! by 7?

  • A.5
  • B.14
  • C.21

Answer: A

From \( 7! \) onward every factorial contains the factor 7, so all of them leave remainder 0.

Only the first six terms matter:

\[ 1 + 2 + 6 + 24 + 120 + 720 = 873 \]

\[ 873 = 7 \times 124 + 5 \]

So the remainder is 5.

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