Discussion
Find the remainder when PP is divided by 9?
Answer: C
We need to find sum of S of the digits of PP.
Till 999 each of the digits from 1 to 9 occurs equal number of times.
Total digit of all the numbers from 1 to 999 will be multiple of ∑9=45.
Hence,
S=45k+(1+0+0+0)
⇒ Required remainder = 1.
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