Discussion
The sum of three consecutive integers is 102. Find the lowest of the three?
Answer: D
Three consecutive numbers can be taken as \((P - 1), P, (P + 1)\)
So, \((P - 1) + P + (P + 1) = 102\)
\(3P = 102 => P = 34\)
The lowest of the three \(= (P - 1) = 34 - 1 = 33\)
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