Discussion
What least number must be added to 1056, so that the sum is completely divisible by 23 ?
Answer: A
Divide and look at the remainder.
\[ 1056 = 23 \times 45 + 21 \]
\[ 23 - 21 = 2 \]
So adding 2 gives \( 1058 = 23 \times 46 \). Adding the remainder itself would make it divisible only by coincidence - it is the shortfall to the next multiple that is wanted.
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