Discussion
The number of distinct prime factors of the largest 6-digit number is
Answer: C
The largest 6-digit number has 5 distinct prime factors.
The largest 6-digit number is 999999.
\[ \begin{aligned} 999999 &= 999 \times 1001 \\ &= (3^{3} \times 37) \times (7 \times 11 \times 13) \end{aligned} \]
The distinct primes are 3, 7, 11, 13 and 37, which is five.
Missing the factor 37 (by stopping at \(999 = 27 \times 37\) without splitting it) is the usual way to get 4; counting powers of 3 as separate factors inflates the count.
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