Discussion
Find the value of B.
\(\begin{array}{r} BA\\ \times\ \ 6\\ \hline C88\end{array}\)
Answer: B
The value of B is 4.
The units digit of A × 6 must be 8, so A is 3 or 8. A = 3 gives 18, and then 6B + 1 must end in 8, which is impossible. A = 8 gives 48 with a carry of 4, so 6B + 4 must end in 8, which needs 6B to end in 4, so B = 4 (24 + 4 = 28, carry 2, C = 2).
\[ 48\times6=288 \]
2, 6 and 1 do not give a product of the form C88.
You can check the result by multiplying: 48 × 6 = 288, which has the form C88 with C = 2. A trial with A = 3 gives 43 × 6 = 258 and 63 × 6 = 378, which end in 8 but do not have 8 in the tens place. So only A = 8 with B = 4 works.
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