Discussion
What will be the output of the program?
import java.util.*;
public class Item12
{
public static void main(String[] args)
{
List<String> l = new ArrayList<String>(
Arrays.asList("a", "b", "c"));
Iterator<String> it = l.iterator();
while (it.hasNext())
{
if (it.next().equals("b")) it.remove();
}
System.out.println(l);
}
}
Answer: D
Correct answer: The program prints [a, c]
Removing through the iterator is the supported way to delete during iteration: the iterator updates its own expected modification count, so no ConcurrentModificationException arises and the traversal continues correctly. The result is the list without "b". Calling l.remove("b") inside the loop instead would have thrown on the next call to next.
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