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Find the odd man out. 10, 25, 45, 54, 60, 75, 80

  • A.10
  • B.45
  • C.54
  • D.75

Answer: C

Every number here is a multiple of 5 except one.

\[ 10,\; 25,\; 45,\; 60,\; 75,\; 80 \;\text{end in 0 or 5} \]

\[ 54 \;\text{does not} \]

So 54 is the odd man out. A quick test for divisibility by 5 is the last digit alone.

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