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Find the odd man out. 1, 4, 9, 16, 23, 25, 36

  • A.9
  • B.23
  • C.25
  • D.36

Answer: B

Each number is a perfect square.

\[ 1 = 1^{2},\; 4 = 2^{2},\; 9 = 3^{2},\; 16 = 4^{2},\; 25 = 5^{2},\; 36 = 6^{2} \]

\[ 23 \text{ lies between } 16 \text{ and } 25 \text{ and is not a square} \]

So 23 is the odd man out.

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