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Find the odd man out. 16, 25, 36, 72, 144, 196, 225

  • A.36
  • B.72
  • C.196
  • D.225

Answer: B

Each number is a perfect square.

\[ 16 = 4^{2},\; 25 = 5^{2},\; 36 = 6^{2},\; 144 = 12^{2},\; 196 = 14^{2},\; 225 = 15^{2} \]

\[ 72 \text{ lies between } 64 \text{ and } 81 \text{ and is not a square} \]

So 72 is the odd man out.

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