Discussion
Find the value of \((51+52+53+...+100)\).
Answer: A
This is the sum of an arithmetic progression.
Number of terms (n) = (100 - 51) + 1 = 50.
Sum = \(\frac{n}{2} \times (\text{first term} + \text{last term}) = \frac{50}{2} \times (51 + 100) = 25 \times 151 = 3775\).
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