Discussion
The product of two numbers is 120 and the sum of their squares is 289. The sum of the two numbers is:
Answer: B
Let the numbers be x and y.
Given, xy = 120 and \(x^2 + y^2 = 289\).
We know that \((x+y)^2 = x^2 + y^2 + 2xy\).
Substitute the given values: \((x+y)^2 = 289 + 2(120) = 289 + 240 = 529\).
Therefore, x + y = \(\sqrt{529} = 23\).
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