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The sum of the digits of a two-digit number is 8. If the digits are reversed, the new number is 36 less than the original number. Find the number.

  • A.26
  • B.62
  • C.35
  • D.53

Answer: B

Let the ten's digit be x and the unit's digit be y.

The number is 10x + y. The reversed number is 10y + x.

Given, x + y = 8 (Equation 1).

Given, (10x + y) - (10y + x) = 36.

9x - 9y = 36, which simplifies to x - y = 4 (Equation 2).

Adding Equation 1 and Equation 2: 2x = 12, so x = 6.

From x + y = 8, we get 6 + y = 8, so y = 2.

The number is 10(6) + 2 = 62.

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