Discussion
Simplify: \( (\frac{1}{2})^{-2} + (\frac{1}{3})^{-2} + (\frac{1}{4})^{-2} \)
Answer: A
A negative exponent inverts the base. \((a/b)^{-n} = (b/a)^n\).
\((\frac{1}{2})^{-2} = (2)^2 = 4\).
\((\frac{1}{3})^{-2} = (3)^2 = 9\).
\((\frac{1}{4})^{-2} = (4)^2 = 16\).
The sum is \(4 + 9 + 16 = 29\).
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