Discussion

If the product of three consecutive integers is 120, then the sum of the integers is:

Answer: C

Let the consecutive integers be \(n-1, n, n+1\).

We need to find three consecutive numbers whose product is 120. We can estimate the cube root of 120. \(5^3=125\), so the numbers should be around 5.

Let's try 4, 5, and 6.

\(4 \times 5 \times 6 = 20 \times 6 = 120\). This is correct.

The integers are 4, 5, and 6.

Their sum is \(4 + 5 + 6 = 15\).

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