Discussion
The Brewster's angle \(i_{B}\) for any interface should lie between
Answer: B
Brewster's angle lies between \(45^{\circ}\) and \(90^{\circ}\).
By Brewster's law \(\tan i_{B} = n\), where \(n\) is the refractive index of the second medium relative to the first. For light going from a rarer to a denser medium (the usual case, such as air to glass), \(n \gt 1\), so \(\tan i_{B} \gt 1\) and \(i_{B} \gt 45^{\circ}\). Since \(\tan\) is finite, \(i_{B} \lt 90^{\circ}\).
For air to glass with \(n = 1.5\), \(i_{B} \approx 56^{\circ}\), inside this range. The ranges starting at \(0^{\circ}\) or ending at \(45^{\circ}\) or below would need \(n \lt 1\).
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