Discussion
A convex mirror has a radius of curvature of 22 cm. An object is placed 14 cm away from the mirror. The lateral magnification of the image will be
Answer: A
The lateral magnification is +0.44.
For a convex mirror with R = 22 cm, the focal length is f = +11 cm. With the object in front, u = -14 cm (New Cartesian convention):
\[ \begin{aligned} \frac{1}{v} &= \frac{1}{f} - \frac{1}{u} = \frac{1}{11} + \frac{1}{14} \\ &= \frac{25}{154} \\ v &= +6.16\ \text{cm} \end{aligned} \]
\[ m = -\frac{v}{u} = -\frac{6.16}{-14} = +0.44 \]
The positive sign shows an erect, virtual image, as a convex mirror always gives; -0.44 has the wrong sign for a convex mirror.
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