Discussion
Seema and Ashutosh set up a simple pendulum in the laboratory to calculate its time period such that the distance between the two extreme positions of the bob is 'D'. Seema observes that the pendulum bob covers distance D/4 in 2 seconds. Ashutosh thinks that Seema made an error while conducting the experiment and repeats it. He observes that the bob covers distance 3D/2 in 10 seconds.
Which of the following is true ?
Answer: B
The correct statement is that the time period calculated by Seema is greater than that calculated by Ashutosh.
In one complete oscillation the bob goes from one extreme to the other and back, covering \(2D\). So each observation gives the period \(T\) as the time per \(2D\).
\[ \begin{aligned} \text{Seema: } T &= 2 \times \frac{2D}{D/4} = 2 \times 8 = 16\ \text{s} \\ \text{Ashutosh: } T &= 10 \times \frac{2D}{3D/2} \approx 13.3\ \text{s} \end{aligned} \]
So Seema's value, 16 s, is greater. Neither is 12 s. The last option is wrong on physics as well: the period of a simple pendulum depends on its length and g, not on the mass of the bob.
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