Discussion
A 555 astable has \( R_{1} = 1 \ \mathrm{k\Omega} \), \( R_{2} = 10 \ \mathrm{k\Omega} \) and \( C = 100 \ \mathrm{nF} \). Its frequency is about
Answer: A
Applying the standard astable relation:
\[ \begin{aligned} f &= \frac{1.44}{(R_{1}+2R_{2})C} \\ &= \frac{1.44}{21000 \times 10^{-7}} \end{aligned} \]
which gives about 686 Hz. The factor of two on the second resistor is what accounts for it appearing in both the charge and the discharge interval, and omitting it is the usual error in this calculation.
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