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What waveform does a unijunction relaxation oscillator naturally produce?

  • A.A sine wave across the capacitor
  • B.A symmetrical square wave at both terminals
  • C.A triangular wave with equal rise and fall times
  • D.A sawtooth across the capacitor and pulses at the base

Answer: D

The capacitor charges slowly through its resistor and discharges almost instantly through the device, giving a sawtooth, while the discharge current through the base resistor appears as a narrow pulse. That pulse is what made the circuit the standard trigger for thyristors. Neither a sine nor a symmetrical square wave arises, and a triangle would need equal charge and discharge paths. Reading a waveform off the charge and discharge paths is quicker than recalling it.

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