Discussion
A tank of \( L = 10 \ \mathrm{\mu H} \) and \( C = 100 \ \mathrm{pF} \) resonates at about
Answer: A
Applying the resonant frequency relation:
\[ f = \frac{1}{2\pi\sqrt{LC}} = \frac{1}{2\pi\sqrt{10^{-15}}} \]
which gives about 5.03 MHz. Because the frequency goes as the reciprocal square root of the product, a hundredfold change in either component moves it only tenfold - which is why a wide tuning range needs a large capacitance ratio and why varactor tuning is so often supplemented by band switching.
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