Discussion
Eliminating the arbitrary constants \( a \) and \( b \) from \( z = ax + by \) gives
Answer: D
Differentiating partially gives \( p = \partial z/\partial x = a \) and \( q = \partial z/\partial y = b \), so substituting back into the original relation removes both constants:
\[ z \;=\; px + qy. \]
Two constants are removed by two differentiations, and the result is of the first order
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