Discussion
The general solution of \( p + q = 0 \) is
Answer: B
The subsidiary equations are \( dx/1 = dy/1 = dz/0 \). The last gives \( z = b \), and the first pair gives \( x - y = a \), so
\[ z \;=\; f(x - y). \]
Checking, \( p = f' \) and \( q = -f' \), which indeed sum to zero. The combination \( x + y \) would satisfy \( p - q = 0 \) instead
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