Discussion
Clairaut's form of a first-order partial differential equation is
Answer: D
Clairaut's form is \( z = px + qy + f(p,q) \), whose complete integral is obtained simply by replacing \( p \) and \( q \) by constants \( a \) and \( b \):
\[ z \;=\; ax + by + f(a,b). \]
The bare \( f(p,q) = 0 \) and the separable \( f(x,p) = g(y,q) \) are two of the other standard types, each with its own recipe
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