Discussion
A string of length 2 m carries waves at 40 m/s. Its fundamental frequency is
Answer: D
The fundamental wavelength is twice the length, so \( \lambda = 4 \) m, and
\[ f \;=\; \frac{c}{\lambda} \;=\; \frac{40}{4} \;=\; 10\ \mathrm{Hz}. \]
Equivalently \( f = c/2L = 40/(2 \times 2) \). Taking the wavelength as the length itself rather than twice it would double the answer to 20 Hz
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