Discussion
A baghouse of \( 900 \) m\(^2\) at an air to cloth ratio of \( 0.033 \) m/s must handle a flow increase to \( 42 \) m\(^3\)/s. The fabric area now required at the same ratio is
Answer: A
Correct answer: 1273 m\( ^2 \)
Holding the ratio constant, the area required rises with the flow:
\[ A = \frac{Q}{v} = \frac{42}{0.033} \approx 1273 \ \mathrm{m}^2 \]The alternative - keeping the existing 900 square metres and accepting a ratio of 0.047 - would raise the pressure drop, push dust into the weave and shorten bag life, which is why fabric area is added rather than the ratio being allowed to drift up.
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