Machine-translated by Google. Questions are authored in English.
Top

Discussion

The external magnetic field \(B_{z}\) is applied to the paramagnetic material containing N number of spin 1/2 particles each having a magnetic dipole moment \(\mu\). The magnetisation \(\langle M \rangle\) of a system is measured at low magnetic field and at sufficiently high temperate. Which of the following statements is correct ?

  • A.magnetization \(\langle M \rangle\) = \(\frac{N\mu^{2}}{k_{B}T}B_{z}\) and susceptibility \(\chi \propto T\)
  • B.magnetization \(\langle M \rangle\) = \(\frac{N\mu^{2}}{k_{B}T}B_{z}\) and susceptibility \(\chi \propto 1/T\)
  • C.magnetization \(\langle M \rangle\) = \(\frac{N\mu}{k_{B}T}B_{z}^{2}\) and susceptibility \(\chi \propto 1/T\)
  • D.magnetization \(\langle M \rangle\) = \(\frac{k_{B}T}{N\mu^{2}}B_{z}\) and susceptibility \(\chi \propto T\)

Answer: B

The correct statement is \(\langle M \rangle = \frac{N\mu^{2}}{k_{B}T}B_{z}\) with \(\chi \propto 1/T\).

For spin-1/2 moments the two energies are \(\mp\mu B_{z}\), and

\[ \begin{aligned} \langle M \rangle &= N\mu\tanh\frac{\mu B_{z}}{k_{B}T} \\ &\approx \frac{N\mu^{2}B_{z}}{k_{B}T} \end{aligned} \]

in the limit \(\mu B_{z} \ll k_{B}T\) (low field, high temperature), using \(\tanh x \approx x\). The magnetisation is linear in the field, and the susceptibility \(\chi = \partial M/\partial B\) varies as \(1/T\): Curie's law.

\(\chi \propto T\) contradicts the Curie law and goes with the inverted expression in the last option. The option with \(N\mu B_{z}^{2}\) is not linear in the field and has the wrong dimensions.

No comment is present. Be the first to comment.
Loading…

Post your comment

Please log in or register to post a comment.