Machine-translated by Google. Questions are authored in English.
Top

Discussion

A gas of \(N\) classical particles that can occupy energy levels, \(\epsilon_{1}\) and \(\epsilon_{2} = \epsilon_{1} + \Delta\) is in equilibrium with a reservoir at temperature \(T\). From the schematics shown below, choose the correct dependence of the internal energy \(U\) on \(T\).

  • A.Internal energy U against T: flat at a non-zero value at low T, then rising steeply and levelling off
  • B.Internal energy U against T: rising from zero ever more steeply with T
  • C.Internal energy U against T: high and flat at low T, then falling towards zero
  • D.Internal energy U against T: flat at a non-zero value at low T, then rising ever more steeply

Answer: A

The correct dependence is (A): U starts flat at a non-zero value, rises, and levels off.

For a classical two-level system the occupation follows the Boltzmann factor, so

\[ \begin{aligned} U &= N\epsilon_{1} + N\Delta\,p_{2} \\ p_{2} &= \frac{e^{-\Delta/k_{B}T}}{1 + e^{-\Delta/k_{B}T}} \end{aligned} \]

At low T almost every particle is in the lower level, so \(U \approx N\epsilon_{1}\), and the rise is exponentially slow until \(k_{B}T\) approaches \(\Delta\). At high T the two levels become equally occupied, so U saturates at \(N(\epsilon_{1} + \Delta/2)\) instead of growing without limit.

(B) and (D) keep rising ever more steeply, as for a system with unlimited levels. (C) has U falling as T rises, which would mean a negative heat capacity.

No comment is present. Be the first to comment.
Loading…

Post your comment

Please log in or register to post a comment.