Discussion
Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56 % of the sum of their marks. The marks obtained by them are:
Answer: C
Their marks be \((x + 9)\) and \(x\)
Then, \(x + 9 = \frac{56}{100}(x + 9 + x)\)
\(\Rightarrow 25(x + 9) = 14(2x + 9) \)
\(\Rightarrow 3x = 99 \)
\(\Rightarrow x = 33\)
So, their marks are 42 and 33.
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