Discussion
The population of a town increased from \(1,75,000\) to \(2,62,500 \) in a decade. The average percent increase of population per year is:
Answer: B
Increase in \(10\) years \(= (262500 - 175000) = 87500.\)
Increase % \(= (\frac{87500}{175000} \times 100)\) % \(= 50\) %
\(\therefore\) Required average \(= (\frac{50}{10})\) % \(= 5\) %
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